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X^2+6X+12=X+2
We move all terms to the left:
X^2+6X+12-(X+2)=0
We get rid of parentheses
X^2+6X-X-2+12=0
We add all the numbers together, and all the variables
X^2+5X+10=0
a = 1; b = 5; c = +10;
Δ = b2-4ac
Δ = 52-4·1·10
Δ = -15
Delta is less than zero, so there is no solution for the equation
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